"Leap year: Given the year number. You need to check if this year is a leap year. If it is, print LEAP, otherwise print COMMON. " - Snackify python coding question

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CODING QUESTION

Given the year number. You need to check if this year is a leap year. If it is, print LEAP, otherwise print COMMON.

The rules in Gregorian calendar are as follows:

  • a year is a leap year if its number is exactly divisible by 4 and is not exactly divisible by 100
  • a year is always a leap year if its number is exactly divisible by 400

Warning. The words LEAP and COMMON should be printed all caps.


SOLUTION

y=int(input())
if y%400==0 or (y%4==0 and not(y%100==0)):
    print('LEAP')
else:
    print('COMMON')

 

Input : 2012

Output : LEAP